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A vertex cover of a graph is a set of vertices such that each edge of the graph is incident to at least one vertex of the set. Now given a graph with several vertex sets, you are supposed to tell if each of them is a vertex cover or not.
Input Specification:
Each input file contains one test case. For each case, the first line gives two positive integers N and M (both no more than 104), being the total numbers of vertices and the edges, respectively. Then M lines follow, each describes an edge by giving the indices (from 0 to N-1) of the two ends of the edge.
After the graph, a positive integer K (<= 100) is given, which is the number of queries. Then K lines of queries follow, each in the format:
Nv v[1] v[2] ... v[Nv]
where Nv is the number of vertices in the set, and v[i]'s are the indices of the vertices.
Output Specification:
For each query, print in a line "Yes" if the set is a vertex cover, or "No" if not.
Sample Input:10 118 76 84 58 48 11 21 49 89 11 02 454 0 3 8 46 6 1 7 5 4 93 1 8 42 2 87 9 8 7 6 5 4 2Sample Output:
NoYesYesNoNo
#include#include using namespace std;int main(){ int n, m, a, b; cin >> n >> m; vector nv[n]; for (int i = 0; i < m; i++) { cin >> a >> b; nv[a].push_back(i); nv[b].push_back(i); } int k, p, t; cin >> k; for (int i = 0; i < k; i++) { bool ans[m]; fill(ans, ans+m, false); cin >> p; for (int j = 0; j < p; j++) { cin >> t; for (int k = 0; k < nv[t].size(); k++) { ans[nv[t][k]] = true; } } bool flag = true; for (int j = 0; j < m; j++) { if (!ans[j]) { flag = false; break; } } if (flag) { cout << "Yes\n"; }else{ cout << "No\n"; } } return 0;}
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